document.write( "Question 102516: Tom is 4 times as old as Todd. In 3 years Tom's age will be 13 years more than 2 times as old as Todd. How old is Tom? \n" ); document.write( "
Algebra.Com's Answer #74585 by mjgulinello(10)![]() ![]() ![]() You can put this solution on YOUR website! Let m = Tom's age \n" ); document.write( "Let d = Todd's age\r \n" ); document.write( "\n" ); document.write( "Now we have to write equations that compare their ages. \n" ); document.write( "We know tom is 4 times as old as Todd, so \n" ); document.write( " \n" ); document.write( "We also know in 3 years Tom's age will be 13 years more than 2 times as old as Todd, so \n" ); document.write( " \n" ); document.write( "Now we can plug the first equation into the second to get: \n" ); document.write( " \n" ); document.write( "Use the distributive property on the right side of the equation. \n" ); document.write( " \n" ); document.write( "Combine like terms \n" ); document.write( " \n" ); document.write( "Subtract 2d from each side \n" ); document.write( " \n" ); document.write( "Subtract 3 from each side \n" ); document.write( " \n" ); document.write( "Divide each side by 2 \n" ); document.write( " \n" ); document.write( "So we now know Todd is 8. We can plug that in to find Tom's age. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Tom is 32. \n" ); document.write( "We can check this by using the second equation. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Check. \n" ); document.write( "That's all for this problem. \n" ); document.write( "-Mike \n" ); document.write( " |