document.write( "Question 96052: 1/2(16x-2)=1/3(81-27x)+6 I need to solve for x. \n" ); document.write( "
Algebra.Com's Answer #74584 by JP(22)\"\" \"About 
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1/2(16x-2)=1/3(81-27x)+6 solve in respect to variable x\r
\n" ); document.write( "\n" ); document.write( "First multiply 1/2 through(16x-2)
\n" ); document.write( "You get (8x-1)as a result because half of 16=8 and half of -2=-1.
\n" ); document.write( "Next, multiply 1/3 through(81-27x) as a result becuase 1/3rd of 81=27 or 81/3 and 1/3rd of 27 is 9 or 27/3.
\n" ); document.write( "At this point you have a problem that looks like this...(8x-1)=(27-9x)+6.
\n" ); document.write( "You can now remove the parentheses, and you have 8x-1=27-9x+6, add 27+6 and you get 33.
\n" ); document.write( "You have 8x-1=33-9x now. Add the -9x(makes it positive now) to the left to get 17x and add -1(makes it positive now) to the right to get 34.\r
\n" ); document.write( "\n" ); document.write( "You have 17x=34 now and you may solve for x.
\n" ); document.write( "divide 17 into 34 (34/17) to isolate the x variable and render a solution.
\n" ); document.write( "x=2 is the solution
\n" ); document.write( "To prove the solution is valid you must plug the solution into every instance of x.
\n" ); document.write( "Use (8x-1)=(27-9x)+6 to make it less complicated
\n" ); document.write( "After plugging in 2 you now have (16-1=27-18+6)
\n" ); document.write( "Which reduces to 15=15, thus proving a valid solution of 2.\r
\n" ); document.write( "\n" ); document.write( "Hope this helps.
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