document.write( "Question 1129240: Kiaria is 7 years older than Jay.
\n" ); document.write( "Martha is twice as old as Kiaria.
\n" ); document.write( "The sum of their three ages is 77.\r
\n" ); document.write( "\n" ); document.write( "Find the ratio of Jay's age to Kiaria's age to martha's age.
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Algebra.Com's Answer #745815 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+k+=+j+%2B+7+\"
\n" ); document.write( "\"+m+=+2k+\"
\n" ); document.write( "\"+k+%2B+j+%2B+m+=+77+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "\"+j+=+k+-+7+\"
\n" ); document.write( "j : k : m = j : k : 2k
\n" ); document.write( "--------------------------
\n" ); document.write( "\"+k+%2B+k+-+7+%2B+2k+=+77+\"
\n" ); document.write( "\"+4k+=+84+\"
\n" ); document.write( "\"+k+=+21+\"
\n" ); document.write( "and
\n" ); document.write( "\"+j+=+k+-+7++\"
\n" ); document.write( "\"+j+=+21+-+7+\"
\n" ); document.write( "\"+j+=+14+\"
\n" ); document.write( "So, \"+j+=+%282%2F3%29%2Ak+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "j : k : m = (2/3)*k : k : 2k
\n" ); document.write( "j : k : m = 2k : 3k : 6k \r
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