document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129238>Question 1129238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation by rewriting the exponential expressions using the indicated logarithm.\r<BR>\n" );
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document.write( "e^4x = 19 using the natural log\r<BR>\n" );
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document.write( "60^e&#8722;0.12t = 10 using the natural log\r<BR>\n" );
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document.write( "*Knowing that the natural log base is 10 the answers that I came up with was: log10=19, but I don't know where the 4 is suppose to go. The same confusion goes for the second one, I thought the equation should be set up as log10=10, but I don't know where 60 and e^-0.12t goes. Can someone explain how to properly set up the equation? Thanks.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745814 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Solve the equation by rewriting the exponential expressions using the indicated logarithm.<BR>\n" );
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document.write( "the natural log base is not 10, it's e, base ten is the \"common log\"<BR>\n" );
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document.write( "assuming<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%284x%29+=+19 ALIGN=MIDDLE  ALT=\"e%5E%284x%29+=+19\"   DISABLED_style= \"max-width:90%; height:auto;\" > using the natural log<BR>\n" );
document.write( "the log equiv of exponents<BR>\n" );
document.write( "4x*ln(e) = ln(19) <BR>\n" );
document.write( "the ln of e = 1, therefore<BR>\n" );
document.write( "4x = ln(19)<BR>\n" );
document.write( "4x = 2.4999<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.4999%2F4 ALIGN=MIDDLE  ALT=\"2.4999%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = .7361<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60%5Ee+-+.12t+=+10 ALIGN=MIDDLE  ALT=\"60%5Ee+-+.12t+=+10\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60%5Ee+=+12t+%2B+10 ALIGN=MIDDLE  ALT=\"60%5Ee+=+12t+%2B+10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "using the natural logs<BR>\n" );
document.write( "e*ln(60) = ln(12t + 10)<BR>\n" );
document.write( "using calc: find e*ln(60)<BR>\n" );
document.write( "11.13 = ln(12t+10) <BR>\n" );
document.write( "find the e^x of both sides<BR>\n" );
document.write( "68186.37 = 12t + 10<BR>\n" );
document.write( "subtract 10 from both sides<BR>\n" );
document.write( "68176.37 = 12<BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=68176%2F12 ALIGN=MIDDLE  ALT=\"68176%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "t = 5681.36<BR>\n" );
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