document.write( "Question 1129228: Mahmoud invested 6000 in two accounts, some of it at 2% simple interest, the rest in an account earning 4% simple interest. How much did he invest in each account if he earned $190 in interest after a year? \n" ); document.write( "

Algebra.Com's Answer #745802 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"P\"$ = amount invested @ 2%
\n" ); document.write( " $\"+6000+-+P+\"$ = amount invested @ 4%
\n" ); document.write( "Let $\"+I+\"$ = interest earned from 2% account
\n" ); document.write( " $\"+190+-+I+\"$ = interest earned from 4% account
\n" ); document.write( "-------------------------------------------------------
\n" ); document.write( "(1) $\"+I+=+P%2A.02%2A1+\"$
\n" ); document.write( "(2) $\"+190+-+I+=+%28+6000+-+P+%29%2A.04%2A1+\"$
\n" ); document.write( "---------------------------------------------
\n" ); document.write( "(2) $\"+190+-+I+=+240+-+.04P+\"$
\n" ); document.write( "(2) $\"+.04P+=+I+%2B+50+\"$
\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) $\"+.04P+=+.02P+%2B+50+\"$
\n" ); document.write( "(2) $\"+.02P+=+50+\"$
\n" ); document.write( "(2) $\"+P+=+2500+\"$
\n" ); document.write( " $\"+6000+-+P+=+3500+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+I+=+.02%2A2500+\"$
\n" ); document.write( "(1) $\"+I+=+50+\"$
\n" ); document.write( "--------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+190+-+50+=+%28+6000+-+2500+%29%2A.04+\"$
\n" ); document.write( "(2) $\"+140+=+3500%2A.04+\"$
\n" ); document.write( "(2) $\"+140+=+140+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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