document.write( "Question 1129189: Find 3 consecutive Integers whose some is 195 \n" ); document.write( "
Algebra.Com's Answer #745769 by greenestamps(13203) You can put this solution on YOUR website! \n" ); document.write( "Both of the other two tutors used n, n+1, and n+2 (or x, x+1, and x+2) for the three consecutive integers. If you are going to solve the problem with formal algebra, it is often easier (as in this case) to let the three integers be x-1, x, and x+1. Then the algebra is a bit easier: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The three integers are x-1=64, x=65, and x+1=66. \n" ); document.write( "In this particular problem, using x-1, x, and x+1 for three consecutive integers only made the problem a bit easier to solve. But in more complicated problems involving consecutive integers, it can make a big difference in the amount of work required to solve the problem. \n" ); document.write( "But note that this problem can be solved using informal logical reasoning MUCH faster than with formal algebra. The exact same calculations are used; but you aren't slowed down with defining variables and solving equations. \n" ); document.write( "In any 3 consecutive integers, the middle one is the average of all three. Since the sum is 195, the average is 195/3 = 65; then the 3 integers are 64, 65, and 66. \n" ); document.write( " |