document.write( "Question 102559This question is from textbook Algebra and Trigonometry
\n" ); document.write( ": Find the domain of f(x)= 7+ the square root of 3x+21, and express it using interval notation. \n" ); document.write( "
Algebra.Com's Answer #74575 by jim_thompson5910(35256)\"\" \"About 
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\"y=7%2Bsqrt%283x%2B21%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "Remember you cannot take the square root of a negative value. So that means the argument \"3x%2B21\" must be greater than or equal to zero (i.e. the argument must be positive)\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B21%3E=0\" Set the inner expression greater than or equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"3x%3E=0-21\"Subtract 21 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3x%3E=-21\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=%28-21%29%2F%283%29\" Divide both sides by 3 to isolate x \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=-7\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So that means x must be greater than or equal to -7\r
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\n" ); document.write( "\n" ); document.write( "So here is the domain in interval notation: [-7,)\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=7%2Bsqrt%283x%2B21%29\" , we get\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-2%2C+18%2C+7%2Bsqrt%283x%2B21%29%29+\" notice how the graph never crosses the line \"x=-7\". So this graphically verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "and we can see that x must be greater than or equal to -7 in order to lie on the graph
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