document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129193>Question 1129193</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The price of a computer is decreasing at an exponential rate. In 1985, a desktop computer cost $2,500. The price of a comparable computer is decreasing by 3.5% every 2 years. During what year is the price of that comparable computer $1,200? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745748 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745748\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The price of a computer is decreasing at an exponential rate. In 1985, a desktop computer cost $2,500. The price of a comparable computer is decreasing by 3.5% every 2 years. During what year is the price of that comparable computer $1,200?<BR>\n" );
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document.write( "1200 = 2500(1-0.035)^(t/2)<BR>\n" );
document.write( "(12/25) = (0.0965)^(t/2)<BR>\n" );
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document.write( "Take the log of both sides::<BR>\n" );
document.write( "(t/2)*log(0.0965) = log(12/25)<BR>\n" );
document.write( "t/2 = -0.3188/-0.0155 = 20.6<BR>\n" );
document.write( "time = 41.2 years<BR>\n" );
document.write( "Ans:: 1985+42 = 2027<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );