document.write( "Question 1129189: Find 3 consecutive Integers whose some is 195 \n" ); document.write( "

Algebra.Com's Answer #745742 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( " let $\"3+\"$ consecutive integers be $\"x\"$ , $\"x%2B1\"$ , and $\"x%2B2\"$ \r
\n" ); document.write( "\n" ); document.write( " if their some is $\"195+\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"x%2Bx%2B1%2Bx%2B2=195\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x%2B3=195\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x=195-3\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x=192\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=192%2F3\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=64\"$ -> first integer
\n" ); document.write( " $\"x%2B1=65\"$ -> second integer
\n" ); document.write( " $\"x%2B2=66\"$ -> third integer\r
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