document.write( "Question 1129131: Three cards labelled 2, 3 and 4 are placed in a hat and a card is drawn. This is repeated 3 times without replacement.
\n" ); document.write( "a) How many 3 digit numbers can be formed
\n" ); document.write( "b) What is the probability that the 3 digit number is odd? divisible by 3? \n" ); document.write( "

Algebra.Com's Answer #745706 by Edwin McCravy(20063) $\"\"$ $\"About$

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Three cards labelled 2, 3 and 4 are placed in a hat and a card is drawn. This is repeated 3 times without replacement.
\n" ); document.write( "a) How many 3 digit numbers can be formed?
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document.write( "These six: 234, 243, 324, 342, 423 and 432\r\n" );
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\n" ); document.write( "b) What is the probability that the 3 digit number is odd?
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document.write( "Only 243 and 423 are odd. That's 2 ways out of 6, or 2/6 which reduces to 1/3.\r\n" );
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\n" ); document.write( "divisible by 3?
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document.write( "234÷3 = 78, so 234 is divisible by 3.\r\n" );
document.write( "243÷3 = 81, so 243 is divisible by 3.\r\n" );
document.write( "324÷3 = 108, so 324 is divisible by 3.\r\n" );
document.write( "342÷3 = 114, so 342 is divisible by 3.\r\n" );
document.write( "423÷3 = 141, so 423 is divisible by 3.\r\n" );
document.write( "432÷3 = 144, so 432 is divisible by 3.\r\n" );
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document.write( "That's 6 ways out of 6, or 6/6 which reduces to 1. So it is certain that any\r\n" );
document.write( "one of the 6 three-digit numbers you pick, that it will be divisible by 3. A\r\n" );
document.write( "probability of an event being 1 means that the event is certain.\r\n" );
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document.write( "Edwin

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