document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129053>Question 1129053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A kayak can travel 32 miles downstream in 4 &#8203;hours, while it would take 8 hours to make the same trip upstream. Find the speed of the kayak in still&#8203; water, as well as the speed of the current. Let k represent the speed of the kayak in still&#8203; water, and let c represent the speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745649 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> k + c is 32 mi/4 hr=8 mi/hr<BR>\n" );
document.write( "k - c is 32 mi/8 hr=4 mi/hr<BR>\n" );
document.write( "add them<BR>\n" );
document.write( "2 k =12 mi/hr<BR>\n" );
document.write( "speed in still water is 6 mi/hr<BR>\n" );
document.write( "current is 2 mi/hr </SPAN>\n" );
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