document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102517>Question 102517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please helpe me solve this math problem: \r<BR>\n" );
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document.write( "Cheryl is thirteen years more than twice as old as Brad. In 11 years the sum of thire ages will be 92. How old is Cheryl now?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74561 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Brad is the youngest, so let his age be x. That means Cheryl is 2x+13 years old.\r<BR>\n" );
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document.write( "In 11 years Brad will be x + 11 years old. Cheryl will be 2x+13+11=2x+24 years old. We also know their ages will sum to 92 at that time, so:\r<BR>\n" );
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document.write( "x+11+2x+24=92<BR>\n" );
document.write( "Simplifying we have:<BR>\n" );
document.write( "3x+35=92<BR>\n" );
document.write( "Subtracting 35 from both sides:<BR>\n" );
document.write( "3x=57<BR>\n" );
document.write( "Dividing by 3:<BR>\n" );
document.write( "x=19\r<BR>\n" );
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document.write( "So, Brad is 19 and Cheryl is 2(19)+13=38+13=51.  \r<BR>\n" );
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document.write( "In 11 years, Brad will be 30 and Cheryl will be 62.\r<BR>\n" );
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document.write( "Checking, we findthat 30+62=92, which is the required check. </SPAN>\n" );
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