document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102517>Question 102517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please helpe me solve this math problem: \r<BR>\n" );
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document.write( "Cheryl is thirteen years more than twice as old as Brad. In 11 years the sum of thire ages will be 92. How old is Cheryl now?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74560 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let C = Cheryl's present age and B = Brad's present age.<BR>\n" );
document.write( "From the problem description, you can write:<BR>\n" );
document.write( "1) C = 2B+13  \"Cheryl is 13 years more than twice as old as Brad\"<BR>\n" );
document.write( "2) (C+11) + (B+11) = 92 \"In 11 years the sum of their ages will be 92\"<BR>\n" );
document.write( "Substitute the C= 2B+13 from equation 1) into equation 2) and solve for B.<BR>\n" );
document.write( "2a) (2B+13)+11 +B+11 = 92  Simplify.<BR>\n" );
document.write( "3B+35 = 92  Subtract 35 from both sides.<BR>\n" );
document.write( "3B = 57  Divide both sides by 3.<BR>\n" );
document.write( "B = 19 This is Brad's present age. Use equation 1) to find Cheryl's present age.<BR>\n" );
document.write( "C = 2B+13<BR>\n" );
document.write( "C = 2(19)+13<BR>\n" );
document.write( "C = 38+13<BR>\n" );
document.write( "C = 51 This is Cheryl's present age. </SPAN>\n" );
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