document.write( "Question 1128948: An open water swimmer can swim 27 miles with an ocean current in the same amount of time it takes to swim nine miles against the same current. Find the speed of the current if the swimmer can swim 4 miles per hour in still water \n" ); document.write( "
Algebra.Com's Answer #745548 by josmiceli(19441)\"\" \"About 
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Let the rate of the current = \"+c+\"
\n" ); document.write( "Swimmer's rate swimming with the current:
\n" ); document.write( "\"+4+%2B+c+\"
\n" ); document.write( "Swimmer's rate swimming against the current:
\n" ); document.write( "\"+4+-+c+\"
\n" ); document.write( "Let \"+t+\" = time in hrs for both trips
\n" ); document.write( "---------------------------------------------
\n" ); document.write( "Swimming with the current:
\n" ); document.write( "(1) \"+27+=+%28+4+%2B+c+%29%2At+\"
\n" ); document.write( "Swimming against the current
\n" ); document.write( "(2) \"+9+=+%28+4+-+c+%29%2At+\"
\n" ); document.write( "------------------------------------
\n" ); document.write( "(1) \"+t+=+27%2F%28+4+%2B+c+%29+\"
\n" ); document.write( "(2) \"+t+=+9%2F%28+4+-+c+%29+\"
\n" ); document.write( "\"+27%2F%28+4+%2B+c+%29+=+9%2F%28+4+-+c+%29+\"
\n" ); document.write( "\"+27%2A%28+4+-+c+%29+=+9%2A%28+4+%2B+c+%29+\"
\n" ); document.write( "\"+3%2A%28+4+-+c+%29+=+4+%2B+c+\"
\n" ); document.write( "\"+12+-+3c+=+4+%2B+c+\"
\n" ); document.write( "\"+4c+=+8+\"
\n" ); document.write( "\"+c+=+2+\"
\n" ); document.write( "The speed of the current is 2 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+t+=+27%2F%28+4+%2B+2+%29+\"
\n" ); document.write( "(1) \"+t+=+9%2F2+\"
\n" ); document.write( "and
\n" ); document.write( "\"+t+=+9%2F%28+4+-+2+%29+\"
\n" ); document.write( "\"+t+=+9%2F2+\"
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( "
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