document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128980>Question 1128980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 2.5 L container has a mixture of 25% alcohol. How many liters of the mixture must be drained out and replaced with pure alcohol in order to obtain a mixture containing 40% alcohol?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745520 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You already have three good responses to your question, all of them involving a moderately complicated algebraic equation.<br><BR>\n" );
document.write( "Here is a MUCH faster and easier way to solve a \"mixture\" problem like this.<br><BR>\n" );
document.write( "(1) You are adding 100% alcohol to 25% alcohol; you want to end up with 40% alcohol.<BR>\n" );
document.write( "(2) 40% is 1/5 of the way from 25% to 100%.  (40-25 = 15; 100-25 = 75; 15/75 = 1/5)<BR>\n" );
document.write( "(3) That means 1/5 of the mixture should be the 100% alcohol that you are adding.<br><BR>\n" );
document.write( "1/5 of the 2.5L capacity of the container is 0.5L.<br><BR>\n" );
document.write( "ANSWER: 0.5L of the 25% alcohol should be drained and replaced with 100% alcohol to get 2.5L of 40% alcohol. </SPAN>\n" );
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