document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128923>Question 1128923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A lead ball is formed into a circular sheet. Find diameter of sheet.\r<BR>\n" );
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document.write( "Ball diameter; 2 in. \r<BR>\n" );
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document.write( "Sheet thickness; 0.01 in. \r<BR>\n" );
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document.write( "A ball is a sphere. \r<BR>\n" );
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document.write( "Volume; 4/3 * pi * r^3 \r<BR>\n" );
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document.write( "Area of circle; pi * r^2 \r<BR>\n" );
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document.write( "4/3 * 3.1416 * 1^3 = 1.3333 * 3.1416 * 1^3 = 4.18869 cu. in. \r<BR>\n" );
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document.write( "Unsure how to proceed.  Non-homework.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745458 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The circular sheet is a very thin cylinder, with height 0.01 inches.<br><BR>\n" );
document.write( "Volume of lead ball (sphere): <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284%2F3%29%28pi%29%28r%5E3%29+=+%284%2F3%29%28pi%29%281%5E3%29+=+%284%2F3%29%28pi%29 ALIGN=MIDDLE  ALT=\"%284%2F3%29%28pi%29%28r%5E3%29+=+%284%2F3%29%28pi%29%281%5E3%29+=+%284%2F3%29%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Volume of circular sheet (cylinder): <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%29%28r%5E2%29%28h%29+=+%28pi%29%28r%5E2%29%280.01%29+=+0.01%28pi%29r%5E2 ALIGN=MIDDLE  ALT=\"%28pi%29%28r%5E2%29%28h%29+=+%28pi%29%28r%5E2%29%280.01%29+=+0.01%28pi%29r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The two volumes are the same:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284%2F3%29pi+=+0.01%28pi%29r%5E2%29 ALIGN=MIDDLE  ALT=\"%284%2F3%29pi+=+0.01%28pi%29r%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3+=+0.01r%5E2 ALIGN=MIDDLE  ALT=\"4%2F3+=+0.01r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+400%2F3 ALIGN=MIDDLE  ALT=\"r%5E2+=+400%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%28400%2F3%29 ALIGN=MIDDLE  ALT=\"r+=+sqrt%28400%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = about 11.55 inches </SPAN>\n" );
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