document.write( "Question 1128897: An investment club invested $7,500 into two simple interest accounts for one year. part of the money was invested at 5% and the remainder was placed in a 6% account. The total interest earned was $380. How much was invested into each account? \n" ); document.write( "
Algebra.Com's Answer #745434 by Boreal(15235)\"\" \"About 
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x at 5%
\n" ); document.write( "7500-x at 6%
\n" ); document.write( "interest is .05x+.06(7500-x)
\n" ); document.write( ".05x-.06x+450=380
\n" ); document.write( "-0.01x=-70
\n" ); document.write( "x=$7000 at 5% or $350 interest per year
\n" ); document.write( "7500-x=500 @ 6% or $30 interest per year. They add to $380
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