document.write( "Question 1095139: ABC is an equilateral triangle in which BC=2cm find perpendicular distance from A to BC \n" ); document.write( "
Algebra.Com's Answer #745421 by Quadratic1600(28)![]() ![]() You can put this solution on YOUR website! Hi\r \n" ); document.write( "\n" ); document.write( "So we know that all sides are the same so AB - BC - AC are all 2cm\r \n" ); document.write( "\n" ); document.write( "If you draw a line from A perpendicularly to BC it will meet at a 90 degree angle. So lets call the point where the line from A meets BC (E)\r \n" ); document.write( "\n" ); document.write( "So BE = 1 and CE = 1\r \n" ); document.write( "\n" ); document.write( "So we have the hypotenuse of either AC or AB depending which side of the triangle you choose to work on - It doesn't matter really as they are both 2\r \n" ); document.write( "\n" ); document.write( "So a^2 + b^2 = c^2 which is also the adjacent^2 + opposite^2 = Hypotenuse^2\r \n" ); document.write( "\n" ); document.write( "We know the hypotenuse so lets rearrange so we get\r \n" ); document.write( "\n" ); document.write( "(2^2) (which is the hypotenuse) - (1^2) (which is the line BE or CE depending on which side you are drawing it) = AE\r \n" ); document.write( "\n" ); document.write( "Ok so\r \n" ); document.write( "\n" ); document.write( "4 - 1 = 3\r \n" ); document.write( "\n" ); document.write( "Now SQR of 3 = AE\r \n" ); document.write( "\n" ); document.write( "You will get a positive and negative value as you are square rooting however you can't have a minus side so it will be the positive value.\r \n" ); document.write( "\n" ); document.write( "Hope this helps \n" ); document.write( " |