document.write( "Question 102510: Solve the system by addition or substitution.
\n" ); document.write( " 3x + 6y = 0
\n" ); document.write( " x = 2/3 (this is a fraction)
\n" ); document.write( "The 6y = 0 and
\n" ); document.write( " x = 2/3 are supposed to be lined up under each other if this helps anyone, it doesnt help me that is why I need your help.
\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #74541 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve the system by addition or substitution.
\n" ); document.write( "3x + 6y = 0
\n" ); document.write( "x = 2/3
\n" ); document.write( "------------
\n" ); document.write( "Substitute to solve for y:
\n" ); document.write( "3(2/3) + 6y = 0
\n" ); document.write( "2 + 6y = 0
\n" ); document.write( "y = -1/3
\n" ); document.write( "-------------
\n" ); document.write( "Solution: x = 2/3; y = -1/3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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