document.write( "Question 102510: Solve the system by addition or substitution.
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document.write( " 3x + 6y = 0
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document.write( " x = 2/3 (this is a fraction)
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document.write( "The 6y = 0 and
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document.write( " x = 2/3 are supposed to be lined up under each other if this helps anyone, it doesnt help me that is why I need your help.
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document.write( "Thank you. \n" );
document.write( "
Algebra.Com's Answer #74541 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve the system by addition or substitution. \n" ); document.write( "3x + 6y = 0 \n" ); document.write( "x = 2/3 \n" ); document.write( "------------ \n" ); document.write( "Substitute to solve for y: \n" ); document.write( "3(2/3) + 6y = 0 \n" ); document.write( "2 + 6y = 0 \n" ); document.write( "y = -1/3 \n" ); document.write( "------------- \n" ); document.write( "Solution: x = 2/3; y = -1/3 \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |