document.write( "Question 102349This question is from textbook Algebra
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document.write( ": A moving van leaves a house traveling at an average rate of 35 mi/h.The family
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document.write( "leaves the house hour later following the same route in a car.They travel at
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document.write( "an average rate of 50 mi/h. How long after the moving van leaves the house will
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document.write( "the car catch up with the van? \n" );
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Algebra.Com's Answer #74540 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A moving van leaves a house traveling at an average rate of 35 mi/h.The family \n" ); document.write( "leaves the house hour later following the same route in a car.They travel at \n" ); document.write( "an average rate of 50 mi/h. How long after the moving van leaves the house will \n" ); document.write( "the car catch up with the van? \n" ); document.write( ": \n" ); document.write( "Let t = travel time of the van when the car overtakes it \n" ); document.write( "then \n" ); document.write( "(t-1) = travel time of the car when this happens \n" ); document.write( ": \n" ); document.write( "They will have traveled the same distance when the car overtakes the van \n" ); document.write( "Write a distance equation from the fact. Distance = speed * time \n" ); document.write( ": \n" ); document.write( "Car dist = van dist \n" ); document.write( "50(t-1) = 35t \n" ); document.write( "50t - 50 = 35t \n" ); document.write( "50t - 35t = +50 \n" ); document.write( "15t = 50 \n" ); document.write( "t = 50/15 \n" ); document.write( "t = 3 \n" ); document.write( ": \n" ); document.write( "Check solution by finding the distance of both, should be equal \n" ); document.write( "Van: 3 \n" ); document.write( "Car: 2 \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |