document.write( "Question 102349This question is from textbook Algebra
\n" ); document.write( ": A moving van leaves a house traveling at an average rate of 35 mi/h.The family
\n" ); document.write( "leaves the house hour later following the same route in a car.They travel at
\n" ); document.write( "an average rate of 50 mi/h. How long after the moving van leaves the house will
\n" ); document.write( "the car catch up with the van?
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Algebra.Com's Answer #74540 by ankor@dixie-net.com(22740)\"\" \"About 
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A moving van leaves a house traveling at an average rate of 35 mi/h.The family
\n" ); document.write( "leaves the house hour later following the same route in a car.They travel at
\n" ); document.write( "an average rate of 50 mi/h. How long after the moving van leaves the house will
\n" ); document.write( "the car catch up with the van?
\n" ); document.write( ":
\n" ); document.write( "Let t = travel time of the van when the car overtakes it
\n" ); document.write( "then
\n" ); document.write( "(t-1) = travel time of the car when this happens
\n" ); document.write( ":
\n" ); document.write( "They will have traveled the same distance when the car overtakes the van
\n" ); document.write( "Write a distance equation from the fact. Distance = speed * time
\n" ); document.write( ":
\n" ); document.write( "Car dist = van dist
\n" ); document.write( "50(t-1) = 35t
\n" ); document.write( "50t - 50 = 35t
\n" ); document.write( "50t - 35t = +50
\n" ); document.write( "15t = 50
\n" ); document.write( "t = 50/15
\n" ); document.write( "t = 3\"1%2F3\" hrs or 3 hrs, 20 min
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the distance of both, should be equal
\n" ); document.write( "Van: 3\"1%2F3\" * 35 = 166\"2%2F3\" miles
\n" ); document.write( "Car: 2\"1%2F3\" * 50 = 166\"2%2F3\" miles\r
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