document.write( "Question 1128867: a rectangle has it breath to be 2x and x+y-11.but it lenght is 3y+2 and x+7. find the value of x and y and find the dimesion of the rectangle \n" ); document.write( "
Algebra.Com's Answer #745390 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "From the condition, we have these two equations\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2x = x + y -11 (1)\r\n" ); document.write( "3y + 2 = x+ 7 (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify each equation\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x - y = -11 (1')\r\n" ); document.write( "-x + 3y = 5 (2')\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Add equations (1') and (2'). You will get\r\n" ); document.write( "\r\n" ); document.write( " 2y = -11 + 5 = -6 ====> y = -6/2 = -3.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then from eq(1') x = y - 11 = -3 - 11 = -14.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Answer. x= -14; y= -3.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "@josgarithmetic correctly noticed that with these values of x and y the dimensions of the \"rectangle\" are negative,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, such a \"rectangle\" does not exist.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is true.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=====================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Every night we have a visitor in the forum who posts frank/candid RUBBISH.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |