document.write( "Question 102510: Solve the system by addition or substitution.
\n" ); document.write( " 3x + 6y = 0
\n" ); document.write( " x = 2/3 (this is a fraction)
\n" ); document.write( "The 6y = 0 and
\n" ); document.write( " x = 2/3 are supposed to be lined up under each other if this helps anyone, it doesnt help me that is why I need your help.
\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #74539 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
\"3x%2B6y=0\"
\n" ); document.write( "\"x=2%2F3\"
\n" ); document.write( "Substituting the value 2/3 into the first equation, we have:
\n" ); document.write( "\"3%282%2F3%29%2B6y=0\", which simplifies to:
\n" ); document.write( "\"2%2B6y=0\".
\n" ); document.write( "Subracting 2 from both sides, we have:
\n" ); document.write( "\"6y=-2\".
\n" ); document.write( "Dividing through by 6:
\n" ); document.write( "\"y=-2%2F6=-1%2F3\"
\n" ); document.write( "Always check. So substitute x=2/3 and y=-1/3 back into the original equation:
\n" ); document.write( "\"3%282%2F3%29%2B6%28-1%2F3%29=2-2=0\". Check.
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