document.write( "Question 102508: Solve the system by addition or substitution.
\n" ); document.write( " –15x + 3y = 9
\n" ); document.write( " y = 3 + 5x \r
\n" ); document.write( "\n" ); document.write( "Please help me with this problem step by step if at all possible then maybe I can actually catch on, on how to do these problems. THANK YOU!!
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Algebra.Com's Answer #74537 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
\"-15x%2B3y=9\"
\n" ); document.write( "\"y=3%2B5x\"
\n" ); document.write( "Subtitution means to plug the value of y from the second equation into the first equation.
\n" ); document.write( "\"-15x%2B3%283%2B5x%29=9\"
\n" ); document.write( "\"-15x%2B9%2B15x=9\"
\n" ); document.write( "Collecting the x's, we end up the tautology:
\n" ); document.write( "\"9=9\", which is not much help to us.
\n" ); document.write( "So, returning to the original equations:
\n" ); document.write( "\"-15x%2B3y=9\"
\n" ); document.write( "\"y=3%2B5x\"
\n" ); document.write( "Subtracing 5x from both sides of the second equation, we have:
\n" ); document.write( "\"-5x+%2B+y+=+3\".
\n" ); document.write( "Aligning the two linear equations:
\n" ); document.write( "\"-15x%2B3y=9\"
\n" ); document.write( "\"-5x%2By=3\"
\n" ); document.write( "Dividing the first equation by 3, we have:
\n" ); document.write( "\"-5x%2By=3\"
\n" ); document.write( "So, we see that we really do not have two equations. We have just one equation. The first and second are just different expressions of the same thing.
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