document.write( "Question 102455: The future population of a town t years after January 1, 1995 is described in thousands by function P(t) = 120 + 4t + 0.05t2. Calculate the value of P(5) and explain it means. \n" ); document.write( "
Algebra.Com's Answer #74534 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This function models the population (in thousands) of a town starting on January 1, 1995. \n" ); document.write( ". \n" ); document.write( "The clock starts running on January 1, 1995. On that date t is equal to zero. So if you go \n" ); document.write( "to the given function and substitute zero for t, you get the population of the town on that \n" ); document.write( "date. Let's do it ... \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So on January 1, 1995 the population of the town is 120 thousand or 120,000. \n" ); document.write( ". \n" ); document.write( "Five years later [you get that from P(5)] is January 1, 2000. We can find the population of \n" ); document.write( "the town on that date by substituting 5 into the given equation in place of t. When we do, the \n" ); document.write( "equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Adding up the three terms tells us that on January 1, 2000 the population of the town is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This means that in the first five years, the town's population grows from 120,000 to \n" ); document.write( "141,250 ... a gain of 21,250. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to see your way through this problem. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |