document.write( "Question 102455: The future population of a town t years after January 1, 1995 is described in thousands by function P(t) = 120 + 4t + 0.05t2. Calculate the value of P(5) and explain it means. \n" ); document.write( "
Algebra.Com's Answer #74534 by bucky(2189)\"\" \"About 
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Given:
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\n" ); document.write( "\"P%28t%29+=+120+%2B+4t+%2B+0.05t%5E2\"
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\n" ); document.write( "This function models the population (in thousands) of a town starting on January 1, 1995.
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\n" ); document.write( "The clock starts running on January 1, 1995. On that date t is equal to zero. So if you go
\n" ); document.write( "to the given function and substitute zero for t, you get the population of the town on that
\n" ); document.write( "date. Let's do it ...
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\n" ); document.write( "\"P%280%29+=+120+%2B+4%2A%280%29+%2B+0.05%2A%280%29%5E2+=+120+%2B+0+%2B+0+=+120\"
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\n" ); document.write( "So on January 1, 1995 the population of the town is 120 thousand or 120,000.
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\n" ); document.write( "Five years later [you get that from P(5)] is January 1, 2000. We can find the population of
\n" ); document.write( "the town on that date by substituting 5 into the given equation in place of t. When we do, the
\n" ); document.write( "equation becomes:
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\n" ); document.write( "Adding up the three terms tells us that on January 1, 2000 the population of the town is:
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\n" ); document.write( "\"120+%2B+20+%2B+1.25+=+141.25+\" thousand or 141,250.
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\n" ); document.write( "This means that in the first five years, the town's population grows from 120,000 to
\n" ); document.write( "141,250 ... a gain of 21,250.
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\n" ); document.write( "Hope this helps you to see your way through this problem.
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