document.write( "Question 1128807: A plane flew for 4 hours against a 10mph wind. It then flew for 3 hours with the same wind. In all the plane flew for 1390 miles. Find the rate of the plane in still air \n" ); document.write( "
Algebra.Com's Answer #745320 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let x be the plane speed in still air, in miles per hour.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the speed with the wind is (x+10) mph, while the speed against the wind is (x-10) mph.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The total distance equation is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 4*(x-10) + 3*(x+10) = 1390 mi,es.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Solve for x.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |