document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128799>Question 1128799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate the function. (Round your answer to four decimal places.)<BR>\n" );
document.write( "f(x) = &#8722;5e^x &#8722; 1, for  f(&#8722;2)\r<BR>\n" );
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document.write( "*I subsitiuted (-2) for x, which transformed the equation into -5^(-2)-1. The answer incorrectly resulted in .0080. Can someone demonstrate the correct method that should be used. thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745302 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(-2)=-5*e^(-2)-1<BR>\n" );
document.write( "e^(-2)=1/e^2=0.1353<BR>\n" );
document.write( "-5e^(-2)-1=-1.6767, rounding at the end </SPAN>\n" );
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