document.write( "Question 1128754: How to solve this problem:\r
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document.write( "The price p of a certain product and the quantity sold x obey the demand equation p = -2/3x + 200 where x is greater than or equal to 0 and less than or equal to 300. Suppose that the cost C of producing x units is C = sqrt(x) / 20 + 800.\r
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document.write( "Assuming that all items produced are sold, find the cost C as a function of the price p. Simply your answer. \n" );
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Algebra.Com's Answer #745300 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The price p of a certain product and the quantity sold x obey the demand equation \n" ); document.write( " p = \n" ); document.write( " Suppose that the cost C of producing x units is C = \n" ); document.write( "Assuming that all items produced are sold, find the cost C as a function of the price p. \n" ); document.write( " Simplify your answer. \n" ); document.write( ": \n" ); document.write( "solve for x \n" ); document.write( " \n" ); document.write( "multiply by 3 \n" ); document.write( "-2x + 600 = 3p \n" ); document.write( "-2x = 3p - 600 \n" ); document.write( "multiply by -1 \n" ); document.write( "2x = -3p + 600 \n" ); document.write( "divide by 2 \n" ); document.write( "x = \n" ); document.write( "we can write it \n" ); document.write( "x = -1.5p + 300 \n" ); document.write( ": \n" ); document.write( "C = \n" ); document.write( "replace x with (-1.5p+300) \n" ); document.write( "C = \n" ); document.write( " \n" ); document.write( " |