document.write( "Question 1128754: How to solve this problem:\r
\n" ); document.write( "\n" ); document.write( "The price p of a certain product and the quantity sold x obey the demand equation p = -2/3x + 200 where x is greater than or equal to 0 and less than or equal to 300. Suppose that the cost C of producing x units is C = sqrt(x) / 20 + 800.\r
\n" ); document.write( "\n" ); document.write( "Assuming that all items produced are sold, find the cost C as a function of the price p. Simply your answer.
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Algebra.Com's Answer #745300 by ankor@dixie-net.com(22740)\"\" \"About 
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The price p of a certain product and the quantity sold x obey the demand equation
\n" ); document.write( " p = \"-2%2F3\"x + 200 where x is greater than or equal to 0 and less than or equal to 300.
\n" ); document.write( " Suppose that the cost C of producing x units is C = \"sqrt%28x%29%2F20\" + 800.
\n" ); document.write( "Assuming that all items produced are sold, find the cost C as a function of the price p.
\n" ); document.write( " Simplify your answer.
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\n" ); document.write( "solve for x
\n" ); document.write( "\"-2%2F3\"x + 200 = p
\n" ); document.write( "multiply by 3
\n" ); document.write( "-2x + 600 = 3p
\n" ); document.write( "-2x = 3p - 600
\n" ); document.write( "multiply by -1
\n" ); document.write( "2x = -3p + 600
\n" ); document.write( "divide by 2
\n" ); document.write( "x = \"-3%2F2\"p + 300
\n" ); document.write( "we can write it
\n" ); document.write( "x = -1.5p + 300
\n" ); document.write( ":
\n" ); document.write( "C = \"sqrt%28x%29%2F20\" + 800
\n" ); document.write( "replace x with (-1.5p+300)
\n" ); document.write( "C = \"sqrt%28-1.5p%2B300%29%2F20+%2B+800\"
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