document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128762>Question 1128762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fish Tank has a length of 50cm, a breadth of 20cm and a height of 30cm.<BR>\n" );
document.write( "a) How many litres of water does the tank hold if the water is kept at a level of 5cm from the top.<BR>\n" );
document.write( "b) the bottom and sides of the tank are glass but it has no top. What is the Total area of the glass used to make the tank (in cm3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745295 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 cm from the top means that the height of the water in the tank is 30 - 5 = 25.<BR>\n" );
document.write( "So we now have: L=50; B=20; H=25 <BR>\n" );
document.write( "(note: \"breadth\" we would call \"width\" but I'll continue to use breadth because that's what you used)<BR>\n" );
document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<BR>\n" );
document.write( "a) At a level of 5 cm from the top the tank holds (volume): 50*20*25 = 25000 cm^3 of water = 250 m^3<BR>\n" );
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document.write( "Question b can be answered in cm^2 but not in cm^3:<BR>\n" );
document.write( "b) One L*B (the bottom, it doesn't have a top) = 50*20 = 1000 cm^2<BR>\n" );
document.write( "Two sides: 20*30*2 = 1200 cm^2<BR>\n" );
document.write( "Front and back: 30*50*2 = 3000 cm^2<BR>\n" );
document.write( "Total: 1000+1200+3000 = 5200 cm^2<BR>\n" );
document.write( " </SPAN>\n" );
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