document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128775>Question 1128775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If g(x) = 4lnx + 1, what is the value of g^-1(ln 81 + 1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745275 by </B><A HREF=/tutors/aboutme.mpl?userid=Shin123><B>Shin123(626)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shin123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shin123><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> g(x)=4lnx +1 g<sup>-1</sup>(ln 81+1)= ? If we let the unknown be y, we get this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=g%5E-1%28ln+81+%2B1%29=y ALIGN=MIDDLE  ALT=\"g%5E-1%28ln+81+%2B1%29=y\"   DISABLED_style= \"max-width:90%; height:auto;\" > Using the definition of an inverse, we can rearrange the equation to make it look like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=g%28y%29=ln+81%2B1 ALIGN=MIDDLE  ALT=\"g%28y%29=ln+81%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" > 4lny+1=ln 81+1 \r<BR>\n" );
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document.write( "4lny=ln 81\r<BR>\n" );
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document.write( "4lny=4ln 3\r<BR>\n" );
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document.write( "lny=ln 3\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=3%29 ALIGN=MIDDLE  ALT=\"highlight%28y=3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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