document.write( "Question 102385: how much pure acid should be mixed with 7 gallons of a 40% acid solution in order to get a 70% acid solution? \n" ); document.write( "
Algebra.Com's Answer #74527 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how much pure acid should be mixed with 7 gallons of a 40% acid solution in order to get a 70% acid solution? \n" ); document.write( "------------------------ \n" ); document.write( "Comment: Follow the acid. \n" ); document.write( "------------------------ \n" ); document.write( "40% solution DATA: \n" ); document.write( "Amt = 7 gallons ; amt of acid = 0.07*7 = 0.49 gallons \n" ); document.write( "--------------- \n" ); document.write( "100% solution DATA; \n" ); document.write( "Amt = x gallos ; amt of acid = x gallons \n" ); document.write( "----------------------- \n" ); document.write( "70% mixture DATA: \n" ); document.write( "amt = x+7 gallons ; amt of acid = 0.70(x+7)= (0.70x + 4.9) gallons \n" ); document.write( "----------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.49 + x = 0.70x + 4.9 \n" ); document.write( "0.30x = 4.41 \n" ); document.write( "x = 14.7 gallons (amt of 100% solution that must be added) \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |