document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128771>Question 1128771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a point (x,y) equidistant from point (-3,8) and the line 5x-4y+3=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745265 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find a point (x,y) equidistant from point (-3,8) and the line L1 5x-4y+3=0\r<BR>\n" );
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document.write( " It's a parabola. The focus is (-3,8) and the directrix is 5x-4y+3 = 0<BR>\n" );
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document.write( " For any point (x,y) the distance to (-3,8) is sqrt((x+3)^2 + (y-8)^2)<BR>\n" );
document.write( " The distance from (-3,8) to the line L1 is |5x -4y +3|/sqrt(41) = 44/sqrt(41)<BR>\n" );
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document.write( "Find the line perpendicular to L1 thru (-3,8), then the intersection of that line and L1.<BR>\n" );
document.write( "Then find the midpoint from (-3,8) to the intersection.<BR>\n" );
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