document.write( "Question 102504This question is from textbook Essentials of Intermediate Algebra for college students
\n" ); document.write( ": What is the slope and y-intercept of the line whose equation is given. Then graph the linear function. y=2x+1\r
\n" ); document.write( "\n" ); document.write( "I do not understand this at all! Could someone please help me? I would greatly appreciate it. Thanks So Much.
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Algebra.Com's Answer #74525 by doukungfoo(195)\"\" \"About 
You can put this solution on YOUR website!
First you have to know what the slope intercept form of the equation of a line is. It looks like this:
\n" ); document.write( "y = mx + b
\n" ); document.write( "m is the slope of the line and
\n" ); document.write( "b is the y intercept
\n" ); document.write( "When we compare it to the equation we are given
\n" ); document.write( "y = 2x + 1
\n" ); document.write( "we can see that the equation we are given is already in slope intercept form and we can easily identify the slope and y intercept.
\n" ); document.write( "y = mx + b
\n" ); document.write( "y = 2x + 1
\n" ); document.write( "So the 2 is in the m's place. That means that the slope of this line is 2 or more correctly 2/1
\n" ); document.write( "There is a 1 in the b's place. That means that the y intercept for this line is at positive 1 on the y axis.
\n" ); document.write( "Now lets put the line on a graph.
\n" ); document.write( "We know the line crosses the y axis at positive 1 so put a dot there. Now the slope is 2/1 so rise up 2 and run over to the right 1. Put a dot here at point (1,3) now take a ruler or straight edge and line up the two dots and draw your line. Like this.\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+2x%2B1%29+\"
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