document.write( "Question 1128744: The graph of
\n" ); document.write( "f(x) = 1/ 3^- x is reflected about the y-axis and compressed vertically by a factor of 1/4.
\n" ); document.write( " What is the equation of the new function, g(x)? \r
\n" ); document.write( "\n" ); document.write( "*I thought the answer would be 1/4 (x-1/3^-x), assuming that the vertical compression variable goes outside of the parentheses and 1/3^x-3 goes inside the equation. This however was wrong. Can someone explain how setting up these types of equations should be done, especially for future references? Thanks.
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Algebra.Com's Answer #745241 by greenestamps(13350)\"\" \"About 
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\n" ); document.write( "To begin with, the given function is in a very unusual form.

\n" ); document.write( "\"1%2F%283%5E%28-x%29%29+=+3%5Ex\"

\n" ); document.write( "But we can, nevertheless, work the problem with the function as given.

\n" ); document.write( "The vertical compression factor becomes a factor outside the parentheses, as you say.

\n" ); document.write( "But what you are doing with the reflection about the y axis makes no sense. Reflecting a function about the y axis changes x to the opposite of x.

\n" ); document.write( "So a reflection of f(x) = 1/3^(-x) about the y axis and a compression vertically by a factor of 1/4 yields

\n" ); document.write( "g(x) = (1/4)(1/(3^x))

\n" ); document.write( "Graphs of f(x) (red) and g(x) (green):

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