document.write( "Question 1128724: A child is running on a moving sidewalk in an airport. When she runs against the sidewalk's motion, she travels 56ft in 8 seconds. When she runs with the sidewalk's motion, she travels 120ft in the same amount of time. What is the rate of the child on a still sidewalk and what is the rate of the moving sidewalk? \n" ); document.write( "

Algebra.Com's Answer #745224 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+r+\"$ = child rate of running
\n" ); document.write( "Let $\"+s+\"$ = rate of the sidewalk
\n" ); document.write( " $\"+r+%2B+s+=+120%2F8+\"$ ft/sec
\n" ); document.write( " $\"+r+-+s+=+56%2F8+\"$ ft/sec
\n" ); document.write( "-------------------------------
\n" ); document.write( " $\"+r+%2B+s+=+15+\"$
\n" ); document.write( " $\"+r+-+s+=+7+\"$
\n" ); document.write( "----------------- Add
\n" ); document.write( " $\"+2r+=+22+\"$
\n" ); document.write( " $\"+r+=+11++\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+11+%2B+s+=+15+\"$
\n" ); document.write( " $\"+s+=+4+\"$
\n" ); document.write( "---------------------
\n" ); document.write( "Child's rate is 11 ft/sec
\n" ); document.write( "Moving sidewalk's rate is 4 ft/sec
\n" ); document.write( " \n" ); document.write( "

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