document.write( "Question 1128668: The length of a rectangle is 10 cm more than the width. If the perimeter of the rectangle is 60cm. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #745205 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Perimeter = 2L + 2W (1) \n" ); document.write( "Length = W + 10 (2) \n" ); document.write( "Substitute in (1) with the equivalence in (2) \n" ); document.write( "2(W + 10) + 2W = 60 \n" ); document.write( "2W + 20 + 2W = 60 \n" ); document.write( "4W = 40 \n" ); document.write( "W = 10 \n" ); document.write( "and L = W + 10 = 10 + 10 = 20 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "Check: \n" ); document.write( "The perimeter is 60: \n" ); document.write( "2L + 2W = 60 \n" ); document.write( "2(20) + 2(10) = 60 Correct \n" ); document.write( " \n" ); document.write( " |