document.write( "Question 1128675: Find the equation of the circle tangent to x+y=3 at (1,2) and through (3,6). \n" ); document.write( "

Algebra.Com's Answer #745173 by Alan3354(69443) $\"\"$ $\"About$

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Find the equation of the circle tangent to x+y=3 at P(1,2) and through Q(3,6).
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\n" ); document.write( "The center of the circle is on the line perpendicular to x+y=3 and thru the point P.
\n" ); document.write( "The center of the circle is on the perpendicular bisector of PQ, so the intersection of those 2 lines is the center.
\n" ); document.write( "The radius is the distance from the center to P or Q.
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