document.write( "Question 1128578: Hi! I have a problem that my professor wants me to solve by completing the square. The problem says: \r
\n" ); document.write( "\n" ); document.write( "A train travels 300 miles at a uniform speed. If its speed had been 15 miles per hour less, the trip would have taken 1 hour and 40 minutes more. Find the actual speed of the train.\r
\n" ); document.write( "\n" ); document.write( "I tried setting it up like this: (x/300)-([x-15]/300)=1.667 \r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #745066 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "(1) Don't use a decimal approximation for the number of hours. Use 5/3 hours.

\n" ); document.write( "(2) Time is distance divided by speed -- not speed divided by distance.

\n" ); document.write( "(3) The greater time is at the lower speed; the the 5/3 hours difference is (time at lower speed) minus (time at higher speed). You have the two expressions in the wrong order in your equation.

\n" ); document.write( "So....

\n" ); document.write( "\"300%2F%28x-15%29+-+300%2Fx+=+5%2F3\"

\n" ); document.write( "Multiply everything by the common denominator, x(x-15); and multiply everything by 3/5 to get rid of the fraction on the right.

\n" ); document.write( "That will give you the quadratic equation which you can solve by completing the square.
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