document.write( "Question 102484This question is from textbook Introductory Algebra for College Students
\n" ); document.write( ": I need help setting up the following problem:
\n" ); document.write( "You invest $6000 in two accounts payinhg 6% and 9% annual interest, respectively. At the end of the year, the accounts earn the same interest. How much was invested at each rate?
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Algebra.Com's Answer #74502 by Fombitz(32388)\"\" \"About 
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I need help setting up the following problem:
\n" ); document.write( "You invest $6000 in two accounts payinhg 6% and 9% annual interest, respectively. At the end of the year, the accounts earn the same interest. How much was invested at each rate?\r
\n" ); document.write( "\n" ); document.write( "Let's say you invest X at 6% and Y at 9%.
\n" ); document.write( "You know that
\n" ); document.write( "1.\"X%2BY=6000\"
\n" ); document.write( "You also know that the interest for each is the same
\n" ); document.write( "\"I%5Bx%5D=X%2A6%2F100=INT\"
\n" ); document.write( "\"I%5By%5D=Y%2A9%2F100=INT\"
\n" ); document.write( "Set them equal to each other.
\n" ); document.write( "\"X%2A6%2F100=Y%2A9%2F100\"
\n" ); document.write( "2.\"X%2A6=Y%2A9\"
\n" ); document.write( "Now you have two equations with two unknowns (X and Y).
\n" ); document.write( "Use Equation (2) and solve for X.
\n" ); document.write( "\"X=9%2AY%2F6=3%2AY%2F2\"
\n" ); document.write( "Substitute into Equation (1)
\n" ); document.write( "1.\"X%2BY=6000\"
\n" ); document.write( "\"3%2AY%2F2%2BY=6000\"Substitute
\n" ); document.write( "\"3%2AY%2B2%2AY=12000\"Multiply both sides by 2.
\n" ); document.write( "\"5%2AY=12000\"Simplify.
\n" ); document.write( "\"cross%285%29%2AY%2Fcross%285%29=12000%2F5\"Multiplicative inverse of 5.
\n" ); document.write( "\"Y=2400\"
\n" ); document.write( "Use equation (1)
\n" ); document.write( "\"X%2BY=6000\"
\n" ); document.write( "\"X=3600\"
\n" ); document.write( "$3600 invested at 6%.
\n" ); document.write( "$2400 invested at 9%.
\n" ); document.write( "$216 made by each account.
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