document.write( "Question 1930: I asked a question about a boxing ring yesterday and have studied up and down on the pythoragean theorum and have gotten nowhere with it. My question is this:
\n" ); document.write( "A boxing ring in the shape of a square, 20 ft on each side. How far apart would the boxers be when they are in opposite corners of the ring?
\n" ); document.write( "I think it would be 20 ft but I cannot figure out how to explain it.
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Algebra.Com's Answer #745 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
draw a square, label the 4 corners clockwise A, B, C and D, starting from any of the corners.\r
\n" ); document.write( "\n" ); document.write( "Assume boxers are in corners A and C, opposite each other. Draw straight line AC\r
\n" ); document.write( "\n" ); document.write( "Now have a right-angled triangle, ABC where AC is the hypotenuse and AB and BC are sides of the ring, each 20ft, so\r
\n" ); document.write( "\n" ); document.write( "\"AC%5E2+=+AB%5E2+%2B+BC%5E2\"
\n" ); document.write( "\"AC%5E2+=+20%5E2+%2B+20%5E2\"
\n" ); document.write( "\"AC%5E2+=+400+%2B+400\"
\n" ); document.write( "\"AC%5E2+=+800\"
\n" ); document.write( "\"AC+=+sqrt%28800%29\"
\n" ); document.write( "AC = 28.28ft approx.\r
\n" ); document.write( "\n" ); document.write( "Jon.
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