document.write( "Question 1128501: Two dice are tossed once,what is the probability of obtaining a sum that is (a) a four (b) a seven (c) an eight. \n" ); document.write( "

Algebra.Com's Answer #744988 by math_helper(2461) $\"\"$ $\"About$

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\n" ); document.write( "There are 6x6 = 36 possible ordered outcomes (1,1), (1,2), (1,3), …, (5,6), (6,6).
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document.write( "2       (1 way:  1 + 1 )\r\n" );
document.write( "3       (2 ways:  1+2, 2+1)\r\n" );
document.write( "4       (3 ways:  1+3, 2+2, 3+1)\r\n" );
document.write( "5       (4 ways)\r\n" );
document.write( "6       (5 ways)\r\n" );
document.write( "7       (6 ways)\r\n" );
document.write( "8       (5 ways)\r\n" );
document.write( "9       (4 ways)\r\n" );
document.write( "10      (3 ways)\r\n" );
document.write( "11      (2 ways)\r\n" );
document.write( "12      (1 way)\r\n" );
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\n" ); document.write( "\n" ); document.write( "a) Pr(sum is 4) = 3/36 = $\"+highlight%28+1%2F12+%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "Parts b and c are found similarly. Message if you need help. \r
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