document.write( "Question 1128508: Assume that a sample is used to estimate a population proportion (p). Find the Margin of Error (E) that corresponds to the given statistics and confidence level. Round the margin of error 4 decimal places.
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document.write( "90% confidence, n= 300, x=140\r
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document.write( "I attempted to find p by dividing x/n and got 0.4666667, ad used that to get 1 which i got 0.54 from but when i did the equation it gave me 0.09xxxx which is not even close to the answers I had to choose from :(. \n" );
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Algebra.Com's Answer #744979 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! \n" ); document.write( "At 90% confidence, the critical z value is approximately 1.645\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How to get this critical value? By looking up a table of values such as this one. For that specific table, look at the bottom row that starts with z. Right above the \"90% confidence level\" we see the value 1.645, which means that 90% of the area is between -1.645 and 1.645 under the normal curve. A table such as the one mentioned should be found in your book (likely the appendix). You can also opt to use a calculator to compute the critical z value through the use of the invNorm function on TI83 and TI84 calculators. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "With z = 1.645, we can find the margin of error E using the formula below \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "where \n" ); document.write( "phat = x/n = 140/300 = 0.4666667\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "E = 1.645*sqrt(0.4666667*(1-0.4666667)/300) \n" ); document.write( "E = 0.04738141553989 \n" ); document.write( "E = 0.0474\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 0.0474 \n" ); document.write( " \n" ); document.write( " |