document.write( "Question 1128494: I did this wrong twice and I am on my final chance to get it right; can someone please assist. Thank you.\r
\n" ); document.write( "\n" ); document.write( "A car travels 560 mi averaging a certain speed. If the car had gone 10 mph​ faster, the trip would have taken 1 hr less. Find the​ car's average speed.
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Algebra.Com's Answer #744964 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Apparently this question is from a course you are taking. Our giving you the answer won't help you learn anything; and presumably learning something is your objective in taking the course.

\n" ); document.write( "It would help us help you if, as you are asked to when you post your question, you told us what you tried to do on the problem.

\n" ); document.write( "Algebraically, if x is the car's speed, then the number of hours taken to drive 560 miles is 560/x. The number of hours to travel the same 560 miles at a speed 10mph faster would be 560/(x+10). And the second time is 1 hour less than the first:

\n" ); document.write( "\"560%2F%28x%2B10%29+=+560%2Fx-1\"

\n" ); document.write( "Multiply through by the least common denominator of all the fractions, x(x+10):

\n" ); document.write( "\"560x+=+560%28x%2B10%29-x%28x%2B10%29\"
\n" ); document.write( "\"560x+=+560x%2B5600-x%5E2%2B10x\"
\n" ); document.write( "\"x%5E2-10x-5600+=+0\"

\n" ); document.write( "Factor into the form (x+?)(x-?) to finish the problem.

\n" ); document.write( "I hope you have learned enough from the course that you can do that....

\n" ); document.write( "If you can't finish, then try finding the answer by logical guess-and-check. Presumably this is a computer based question, and only an answer is needed; it doesn't matter how you get the answer. (Well... if you want to learn from the course, it matters; but if you just need the right answer, you can guess it.)

\n" ); document.write( "You need two numbers -- a reasonable highway speed in mph and a reasonable number of hours -- whose product is 560. Then you need another speed 10mph faster and another number of hours that is 1 less, whose product is again 560.

\n" ); document.write( "A little playing with \"nice\" numbers should allow you to guess the answer to the problem.
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