document.write( "Question 1128491: Isabelle paid for her $1.75 lunch with 87 coins. If all the coins were nickels and pennies , how many were there of each type of coin \n" ); document.write( "
Algebra.Com's Answer #744954 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Algebraically.... \n" ); document.write( "let n = number of nickels \n" ); document.write( "then (87-n) = number of pennies \n" ); document.write( "The total value of the coins (5 cents for each nickel and 1 cent for each penny) was $1.75 = 175 cents. Write and solve the equation that says that: \n" ); document.write( " \n" ); document.write( "You can finish the formal solution. \n" ); document.write( "Informally, using logical reasoning.... \n" ); document.write( "(1) If all 87 coins were pennies, that would be only 87 cents; the actual total of 175 cents is 175-87 = 88 cents more than that. \n" ); document.write( "(2) Exchanging a penny for a nickel keeps the same total of 87 coins but increases the total value by 4 cents. \n" ); document.write( "(3) To make up those other 88 cents, the number of nickels needed is 88/4 = 22. \n" ); document.write( "ANSWER: She used 22 nickels and 87-22 = 65 dimes. \n" ); document.write( "CHECK: 22(5)+65(1) = 110+65 = 175 \n" ); document.write( " |