document.write( "Question 1128475: Sarah Meeham blends coffee for​ Tasti-Delight. She needs to prepare 150 pounds of blended coffee beans selling for ​$4.47 per pound. She plans to do this by blending together a​ high-quality bean costing ​$5.00 per pound and a cheaper bean at ​$3.00 per pound. To the nearest​ pound, find how much​ high-quality coffee bean and how much cheaper coffee bean she should blend. \n" ); document.write( "
Algebra.Com's Answer #744942 by stanbon(75887)\"\" \"About 
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Sarah Meeham blends coffee for​ Tasti-Delight. She needs to prepare 150 pounds of blended coffee beans selling for ​$4.47 per pound. She plans to do this by blending together a​ high-quality bean costing ​$5.00 per pound and a cheaper bean at ​$3.00 per pound. To the nearest​ pound, find how much​ high-quality coffee bean and how much cheaper coffee bean she should blend.
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity:: H + L = 150 lbs
\n" ); document.write( "Value::: 5H + 3L = 4.47*150
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\n" ); document.write( "Modify to solve for \"H\"::
\n" ); document.write( "3H + 3L = 3*150
\n" ); document.write( "5H + 3L = 4.47*150
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\n" ); document.write( "Subtract and solve for \"H\"
\n" ); document.write( "2H = 1.47*150
\n" ); document.write( "2H = 110.25
\n" ); document.write( "H = 55.125 lbs (amt. of high-quality beans needed)
\n" ); document.write( "Solve for \"L\"::
\n" ); document.write( "L = 150-55.125 = 94.875 lb (amt. of lower quality beans needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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