document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128224>Question 1128224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If (sqrt 3 - 1) is a root of the equation 2x^2-2kx+4 = 0, then k equals... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744931 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "If (sqrt 3 - 1) is a root of the equation 2x^2-2kx+4 = 0, then k equals...<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\"><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28matrix%281%2C3%2C+k%2C+%22=%22%2C+3.46%29%29 ALIGN=MIDDLE  ALT=\"highlight_green%28matrix%281%2C3%2C+k%2C+%22=%22%2C+3.46%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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