document.write( "Question 1128459: john age is 2 years more than twice Mai's age and the sum of their age is 32 years. How old is each? \n" ); document.write( "

Algebra.Com's Answer #744917 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "ANSWER. John is 22 years old; Mai is 10 years old.\r
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document.write( "For a minute, take off 2 years from the John's age.\r\n" );
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document.write( "Then you have two quantities:  the \"corrected\" John's age and the Mia's age.\r\n" );
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document.write( "The first quantity is 2 times the second and they sum up to 32-2 = 30.\r\n" );
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document.write( "x + 2x = 30  ====>  3x = 30  ====>  x = 30/3 = 10.\r\n" );
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document.write( "Thus Mia is 10 years old and John is 2x + 2 = 2*10 + 2 = 22 years old.\r\n" );
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