document.write( "Question 1128428: At noon a horse and buggy headed north at 10 miles per hour. Two hours later, the roadster headed south from the same location at 30 miles per hour. At what time will the horse and buggy be 80 miles from the roadster? \n" ); document.write( "

Algebra.Com's Answer #744883 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+t+\"$ = time in hrs for for the roadster to
\n" ); document.write( "be 80 mi from horse & buggy
\n" ); document.write( "Let $\"+d+\"$ = distance in miles the roadster
\n" ); document.write( "travels in $\"+t+\"$ hrs
\n" ); document.write( " $\"+10%2A2+=+20+\"$ mi is the horse & buggy's head start
\n" ); document.write( "---------------------------
\n" ); document.write( "Equation for Horse & buggy:
\n" ); document.write( "(1) $\"+80+-+d+-+20+=+10t+\"$
\n" ); document.write( "Equation for roadster:
\n" ); document.write( "(2) $\"+d+=+30t+\"$
\n" ); document.write( "---------------------------
\n" ); document.write( "(1) $\"+80+-+30t+-+20+=+10t+\"$
\n" ); document.write( "(1) $\"+40t+=+60+\"$
\n" ); document.write( "(1) $\"+t+=+1.5+\"$
\n" ); document.write( "The roadster left at 2 pm
\n" ); document.write( "2 pm + 1.5 hrs = 3:30 pm
\n" ); document.write( "At 3:30 pm they are 80 mi apart
\n" ); document.write( "-----------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+80+-+d+-+20+=+10%2A1.5+\"$
\n" ); document.write( "(1) $\"+60+-+d+=+15+\"$
\n" ); document.write( "(1) $\"+d+=+45+\"$ mi
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+d+=+30%2A1.5+\"$
\n" ); document.write( "(2) $\"+d+=+45+\"$ mi
\n" ); document.write( "OK\r
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