document.write( "Question 1060690: Sam's age is 4 years more than twice the age of Dave The sum of their ages is 46. What are their ages?\r
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Algebra.Com's Answer #744875 by ikleyn(52800)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "It can be easy solved MENTALLY without using equations.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " Take for a minute these 4 extra years aside.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Then Sam's \"corrected\" age will be twice the Dave's age, and the sum of ages will be 46 - 4 = 42.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Then it is clear that Dave's age is one third of 42, i.e. 14 years, while Sam's \"corrected\" age is 28 years.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Now the last step is to return to Sam his 4 years back to get the \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Answer. Sam is 32 years old; Dave is 14 years old.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Completed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |