document.write( "Question 1128409: if 2 percent of elective bulbs manufactured by a certain company are defective,
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Algebra.Com's Answer #744867 by Edwin McCravy(20060)\"\" \"About 
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if 2 percent of elective bulbs manufactured by a certain company are defective,
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document.write( "The probability that less than 2 are defective is the probability that\r\n" );
document.write( "all 200 bulbs are good OR that there is exactly 1 bad bulb and 199 good \r\n" );
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document.write( "The probability that a bulb is defective is 0.02,\r\n" );
document.write( "The probability that a bulb is good is therefore 1.00-0.02 = 0.98,\r\n" );
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document.write( "The probability that all 200 are good is (0.98)200 = 0.0175879466\r\n" );
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document.write( "The probability that the 1st bulb is bad and the 2nd-200th\r\n" );
document.write( "bulbs are good is (0.02)(0.98)199 = 0.0003589376858\r\n" );
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document.write( "The probability that the 2nd bulb is bad and the 1st and the 3rd-200th bulbs \r\n" );
document.write( "are good is also 0.0003589376858.\r\n" );
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document.write( "...\r\n" );
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document.write( "And it's the same for any 1 bulb being bad, and the other 199 bulbs being\r\n" );
document.write( "good so the probability is 200 times 0.0003589376858 or 0.0717875372\r\n" );
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document.write( "So adding the probability of 'none bad' and the probability of 'exactly 1 bad'\r\n" );
document.write( "gives\r\n" );
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document.write( "0.0175879466 + 0.0717875372 = 0.0721464748  <--final answer\r\n" );
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document.write( "Edwin
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