document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1128255>Question 1128255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f={(1,2),(2,3),(3,3)},g={(1,0)(2,3),(3,2),(4,8)}<BR>\n" );
document.write( "Find the range of f+g= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #744730 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13334)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=744730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "f+g is only defined for values of x in the domains of both f and g: {1,2,3}.  f+g is not defined for x=4, because 4 is in the domain of only g, not f.<br><BR>\n" );
document.write( "We aren't going to run into any problems with function values being undefined for the function f+g, so there will be three values in the range of f+g.<br><BR>\n" );
document.write( "(f+g)(1) = 2+0 = 2<BR>\n" );
document.write( "(f+g)(2) = 3+3 = 6<BR>\n" );
document.write( "(f+g)(3) = 3+2 = 5<br><BR>\n" );
document.write( "ANSWER: The range of f+g is {2,5,6} </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );